11 times nine times 8. 792. And so there are 792 different ways that we could select.
You asked, how many ways can a team of 5 basketball players be selected from 12 people? There are 12 people on a basketball team, and the coach needs to choose 5 to put into a game. a. How many different possible ways can the coach choose a team of 5 players? 12C2 = 792 ways the coach can choose a team of 5.
Amazingly, how many groups of 5 basketball players can be selected from a team of 10 players? There are 252 ways to select a committee of five members from a group of 10 people.
Best answer for this question, how many ways can a basketball team of 5 players be chosen from 8 players *? We have to select 5 players from (8 – 1) = 7 players. ∴ The required number of ways is 21.
Frequent question, how many teams of 7 players can be selected from a squad 10? (7!) = 10 · 9 · 8 7! 5 · 2 · 3 · 3 · 8 120 combinations available from 10 players.
How many ways can a team of 4 players be chosen from 10 people?
10*9*8*7 = 5040. So there is 5040 ways to pick 4 people from a starting pool of 10.
How many ways can a group of 5 be chosen from 25?
Answer: 5! (5*4*3*2*1). So we will need to divide 6,375,600 by 5! Thus, we come up with the number 53,130.
How many ways can 5 basketball players?
The number of ways in which 5 basketball players can be selected from 8 basketball players is 8C5=56 8 C 5 = 56 . Using the product rule, the total number of ways in which both these selections can be made is 330∗56=18480 330 ∗ 56 = 18480 .
How many ways are there to select the starting 5 basketball players from a pool of 15 men who can play all of the positions?
The answer is 120 ways.
How many ways are there to select five players from 10 players?
Therefore, the number of ways of selecting a committee of 5 members from a group of 10 persons is 252.
How many ways can you split 12 players into two teams of 6 players each?
of ways are 12C4*8C4*1/3! i.e. 495*70*1 /6=5775 ways. Divided by 3!
How many ways can you split 10 players into two teams of 5 players each?
Solution. There are (105)=10×9×8×7×65×4×3×2×1=252 ways of chosing the starting five.
How many ways can 5 basketball players be chosen from a group of 9 players?
9-5!) = 126. Your final answer is 126 ways.
How many ways can a team of 5 players be chosen from a group of 15 students?
So, there are 3003 ways of picking 5 people from a group of 15.
How many different combinations are possible if 3 players are selected from a team of 9?
In the end, we see that there are 84 ways to pick 3 people from a group of 9 as long as order does not matter. Consider another example.
